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x^2-(4x+1/5)^2+5x=41
We move all terms to the left:
x^2-(4x+1/5)^2+5x-(41)=0
We add all the numbers together, and all the variables
x^2-(+4x+1/5)^2+5x-41=0
We add all the numbers together, and all the variables
x^2+5x-(+4x+1/5)^2-41=0
We multiply all the terms by the denominator
x^2*5)^2+5x*5)^2-(+4x+1-41*5)^2=0
We add all the numbers together, and all the variables
x^2*5)^2+5x*5)^2-(4x-204)^2=0
Wy multiply elements
25x^4=0
We do not support expression: x^4
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